question_answer

\[{{C}_{4}}{{H}_{10}}O\] has how many isomeric alcohols?

A) \[1\]                                     

B) \[2\]

C) \[3\]                                     

D)  \[4\]

Correct Answer: D

Solution :

\[{{C}_{4}}{{H}_{10}}O\] form total seven isomers (four alcohol) \[+\] three ether) (1) \[C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}C{{H}_{2}}OH\] (2) \[C{{H}_{2}}-\underset{\begin{smallmatrix}  | \\  OH \end{smallmatrix}}{\mathop{C}}\,H-C{{H}_{2}}-C{{H}_{3}}\] (3) (4)