A) \[A{{g}_{2}}S{{O}_{4}}\]
B) \[CuS{{O}_{4}}\]
C) \[PbS{{O}_{4}}\]
D) \[CdS{{O}_{4}}\]
Correct Answer: B
Solution :
\[CuS{{O}_{4}}\]reacts with\[KI\]to give\[{{I}_{2}}\]as: \[2CuS{{O}_{4}}+4KI\xrightarrow{{}}2CuI+{{K}_{2}}S{{O}_{4}}+{{I}_{2}}\]
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