JCECE Engineering JCECE Engineering Solved Paper-2006

  • question_answer
    Ratio of kinetic energy of hydrogen and helium gas at \[300\,\,K\] is:

    A) \[2:1\]                                  

    B) \[4:5\]

    C) \[1:1\]                                  

    D)  \[1:2\]

    Correct Answer: C

    Solution :

    \[KE=\frac{3}{2}nRT\] \[KE\propto n\]                \[KE\propto \frac{w}{M}\]                 \[\frac{{{K}_{{{H}_{2}}}}}{{{H}_{He}}}=\frac{{{M}_{He}}}{{{M}_{H2}}}=\frac{2}{2}=\frac{1}{1}\]                 \[K{{E}_{{{H}_{2}}}}:K{{E}_{He}}=-1:1\]


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