A) form a triangle
B) are only concurrent
C) are concurrent with on line bisecting the angle between the other two
D) none of the above
Correct Answer: B
Solution :
For the two lines \[24x+7y-20=0\] and \[4x-3y-2=0\], the angle bisects are given by \[\frac{24x-7y-20}{25}=\pm \frac{4x-3y-2}{5}\] Taking positive sign, we get \[2x+11y-5=0\] \[\therefore \]The given three lines are concurrent with on line bisecting the angle between the other two
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