2. Solved Papers
  3. JCECE Engineering

JCECE Engineering JCECE Engineering Solved Paper-2006

  • question_answer
    A straight line through the point\[(2,\,\,2)\]intersects the line\[\sqrt{3}x+y=0\]and\[\sqrt{3}x-y=0\]at the points\[A\]and\[B\]. The equation to the line\[AB\], so that triangle\[AOB\]is equilateral is:

    A) \[x-2=0\]                            

    B) \[y-2=0\]

    C) \[x+y-4=0\]                       

    D)  none of these

    Correct Answer: A

    Solution :

    \[\sqrt{3}x+y=0\]makes an angle of \[{{120}^{o}}\] with \[OX\] and \[\sqrt{3}x-y=0\] makes an angle\[{{60}^{o}}\] with\[OX\]. So, the required line is\[y-2=0\]


You need to login to perform this action.
You will be redirected in 3 sec spinner