A) remain unchanged
B) increase
C) decrease
D) become erratic
Correct Answer: B
Solution :
Length of simple pendulum \[=\] Distance between point of suspension and centre of gravity of system On draining off a little mercury, the centre of gravity gets lowered, that is, the length of simple pendulum increases. The time period of simple pendulum is given by \[T=2\pi \sqrt{\frac{l}{g}}\] \[\Rightarrow \] \[T\propto \sqrt{l}\] As length of simple pendulum increases, the time period increases.
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