JCECE Engineering JCECE Engineering Solved Paper-2007

  • question_answer
    The current in the given circuit is

    A) \[0.3\,\,A\]                        

    B) \[0.1\,\,A\]

    C)  \[0.4\,\,A\]                       

    D)  \[0.2\,\,A\]

    Correct Answer: B

    Solution :

    Key Idea: Emf's of cells in the given circuit are in opposite directions, hence resultant emf is difference of the two emf's. We know that when current flowing is same then resistors are connected in series, hence resultant resistance is                 \[R'={{R}_{1}}+{{R}_{2}}=10\Omega +20\Omega \] Also since cells are connected in opposite direction, the resultant emf is                 \[E={{E}_{1}}-{{E}_{2}}\]                     \[=5V-2V=3V\] From ohm's law\[E=IR\] \[\Rightarrow \]               \[I=\frac{E}{R}=\frac{3}{30}=0.1\,\,A\]


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