A) \[1\]
B) \[3\]
C) \[2\]
D) \[64\]
Correct Answer: D
Solution :
Given four numbers \[1,\,\,\,2,\,\,\,3\] and\[4\]. One digit number that can be formed\[^{4}{{P}_{1}}=4\] Two digit numbers \[{{=}^{4}}{{P}_{2}}=12\] Three digit numbers \[{{=}^{4}}{{P}_{3}}=24\] and four digit numbers \[{{=}^{4}}{{P}_{4}}=24\] \[\therefore \]Total number of numbers that can be formed \[=4+12+24+24=64\]
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