question_answer

If the radius of the circumcircle of an isosceles triangle \[PQR\] is equal to\[PQ=PR\], then the angle \[P\] is

A) \[\frac{\pi }{6}\]                                              

B) \[\frac{\pi }{3}\]

C) \[\frac{\pi }{2}\]                                              

D) \[\frac{2\pi }{3}\]

Correct Answer: B

Solution :

Since, radius of circumcircle made by the perpendicular distance Since,    \[PQ=PR\]           \[\therefore \]  \[\angle P=\frac{\pi }{3}\]