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JCECE Engineering JCECE Engineering Solved Paper-2008

  • question_answer
    If a rubber ball is taken at the depth of \[200\,\,m\] in a pool, its volume-decreases by \[0.1%\]. If the density of water is \[1\times {{10}^{3}}kg/{{m}^{3}}\] and \[g=10\,\,m/{{s}^{2}}\], then the volume of elasticity in \[N/{{m}^{2}}\] will be

    A) \[{{10}^{8}}\]                                    

    B) \[2\times {{10}^{8}}\]

    C)  \[{{10}^{9}}\]                                   

    D)  \[2\times {{10}^{9}}\]

    Correct Answer: D

    Solution :

    \[K=\frac{\Delta p}{\Delta V/V}=\frac{\rho hg}{\Delta V/V}\]      \[=\frac{200\times {{10}^{3}}\times 10}{0.1/100}\]       \[=2\times {{10}^{9}}\]


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