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JCECE Engineering JCECE Engineering Solved Paper-2008

  • question_answer
    At \[100\,\,K\]and \[0.1\] atmospheric pressure, the volume of helium gas is\[10\,\,L\]. If volume and pressure are doubled its temperature will change to

    A) \[400\,\,K\]                       

    B)  \[127\,\,K\]

    C)  \[200\,\,K\]                      

    D)  \[25\,\,K\]

    Correct Answer: A

    Solution :

    \[pV=nRT\] \[\Rightarrow \]               \[pV\propto T\] If p and \[V\] are doubled then \[T\] becomes four times\[ie,\] \[{{T}_{2}}=4{{T}_{1}}=4\times 100=400\,\,K\]


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