A) \[5.49\times {{10}^{1}}C\]of electricity
B) \[5.49\times {{10}^{4}}C\]of electricity
C) \[1.83\times {{10}^{7}}C\]of electricity
D) \[5.49\times {{10}^{7}}C\]of electricity
Correct Answer: D
Solution :
\[A{{l}^{3+}}+3{{e}^{-}}\xrightarrow{{}}Al\] \[w=zQ\] where, \[w=\]amount of metal \[w=5.12\,\,kg=5.12\times {{10}^{3}}kg\] \[z=\]electrochemical equivalent \[z=\frac{Equivalent\,\,weight}{96500}=\frac{Atomic\,\,mass}{Electrons\times 96500}\] \[z=\frac{27}{3\times 96500}\] \[5.12\times {{10}^{3}}=\frac{27}{3\times 96500}\times Q\] \[Q=\frac{5.12\times {{10}^{3}}\times 3\times 96500}{27}C\] \[=5.49\times {{10}^{7}}C\]
You need to login to perform this action.
You will be redirected in
3 sec
