A) \[40\,\,mL\]
B) \[20\,\,mL\]
C) \[10\,\,mL\]
D) \[4\,\,mL\]
Correct Answer: A
Solution :
Equivalent weight of oxalic acid\[=126/2\] \[(\because \]Basicity of oxalic acid\[=2)\] Normality of oxalic acid solution\[=\frac{6.3\times 1000}{63\times 250}\] \[=0.4\,\,N\] \[{{N}_{1}}{{V}_{1}}={{N}_{2}}{{V}_{2}}\] (Acid) (Base) \[0.4\times 10\,\,mL=0.1\times {{V}_{2}}\] \[{{V}_{2}}=40\,\,mL\]
You need to login to perform this action.
You will be redirected in
3 sec
