A) Acetone
B) Acetic acid
C) Acetonitrile
D) Acetamide
Correct Answer: C
Solution :
[a]\[\underset{s{{p}^{3}}}{\mathop{C{{H}_{3}}}}\,-\underset{s{{p}^{2}}}{\mathop{\overset{\begin{smallmatrix} O \\ || \end{smallmatrix}}{\mathop{C}}\,}}\,-\underset{s{{p}^{3}}}{\mathop{C{{H}_{3}}}}\,\] [b]\[\underset{s{{p}^{3}}}{\mathop{C{{H}_{3}}}}\,-\underset{s{{p}^{2}}}{\mathop{\overset{\begin{smallmatrix} O \\ || \end{smallmatrix}}{\mathop{C}}\,}}\,-OH\] [c]\[\underset{s{{p}^{3}}}{\mathop{C{{H}_{3}}}}\,-\underset{sp}{\mathop{C}}\,\equiv N\] [d]\[\underset{s{{p}^{3}}}{\mathop{C{{H}_{3}}}}\,-\underset{s{{p}^{2}}}{\mathop{\overset{\begin{smallmatrix} O \\ || \end{smallmatrix}}{\mathop{C}}\,}}\,-N{{H}_{2}}\] Acetonitrile does not contain \[s{{p}^{2}}-\]hybridised carbon.
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