A) \[2n\pi \pm \frac{\pi }{6},\,\,n\in I\]
B) \[2n\pi +\frac{7\pi }{4},\,\,n\in I\]
C) \[n\pi +{{(-1)}^{n}}\frac{\pi }{3},\,\,n\in I\]
D) \[n\pi +{{(-1)}^{n}}\frac{\pi }{4},\,\,n\in I\]
Correct Answer: B
Solution :
Key Idea If \[\cos \theta \] is positive and \[\tan \theta \] is negative, then the angle lies in the \[IVth\] quadrant. Here, we have\[\cos \theta =\frac{1}{\sqrt{2}},\,\,\tan \theta =-1\] \[\therefore \]It lies in the \[IVth\] quadrant \[\Rightarrow \] \[\theta ={{315}^{o}}=\frac{7\pi }{4}\] \[\therefore \]The general value of \[\theta \] is \[2n\pi +\frac{7\pi }{4},\,\,n\in I\]
You need to login to perform this action.
You will be redirected in
3 sec
