A) trigonal bipyramidal
B) tetrahedral
C) pyramidal
D) square planar
Correct Answer: C
Solution :
\[k=\frac{2.303}{t}\log \frac{{{A}_{0}}}{A}\] \[=\frac{2.303}{40}\log \frac{0.1}{0.005}\] \[=\frac{2.303}{40}\log 20=0.075\]
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