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JCECE Engineering JCECE Engineering Solved Paper-2009

  • question_answer
    \[\underset{x\to {{2}^{+}}}{\mathop{\lim }}\,\frac{|x-2|}{x-2}\]is equal to

    A) \[-1\]                                    

    B) \[1\]

    C) \[2\]                                     

    D) \[-2\]

    Correct Answer: B

    Solution :

    \[\underset{x\to {{2}^{+}}}{\mathop{\lim }}\,\frac{|x-2|}{x-2}=\underset{x\to {{2}^{+}}}{\mathop{\lim }}\,\frac{x-2}{x-2}=1\]


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