A) \[36({{x}^{2}}+{{y}^{2}})={{(x-y)}^{2}}\]
B) \[12({{x}^{2}}+{{y}^{2}})={{(x+y)}^{2}}\]
C) \[9({{x}^{2}}+{{y}^{2}})=4{{(x+y)}^{2}}\]
D) None of the above
Correct Answer: A
Solution :
The required equation of lines joining the origin to the point of intersection of \[y=x+3\] and \[4{{x}^{2}}+4{{y}^{2}}=1\] is \[4{{x}^{2}}+4{{y}^{2}}={{\left( \frac{y-x}{3} \right)}^{2}}\] \[\Rightarrow \] \[36({{x}^{2}}+{{y}^{2}})={{(x-y)}^{2}}\]
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