A) \[{{\lambda }_{ph}}>{{\lambda }_{el}}\]
B) \[{{\lambda }_{ph}}<{{\lambda }_{el}}\]
C) \[{{\lambda }_{ph}}={{\lambda }_{el}}\]
D) \[\frac{{{\lambda }_{el}}}{{{\lambda }_{ph}}}=c\]
Correct Answer: A
Solution :
Wavelength of photon will be greater than that of electron because mass of photon is less than that of electron \[\Rightarrow \] \[{{\lambda }_{ph}}>{{\lambda }_{el}}\]
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