A) \[6:5\]
B) \[5:6\]
C) \[3:2\]
D) \[2:3\]
Correct Answer: A
Solution :
As we know, current density\[J=nqv\] \[\Rightarrow \] \[{{J}_{e}}={{n}_{e}}q{{v}_{e}}\] and \[{{J}_{h}}={{n}_{h}}q{{v}_{h}}\] \[\Rightarrow \] \[\frac{{{J}_{e}}}{{{J}_{h}}}=\frac{{{n}_{e}}}{{{n}_{h}}}\times \frac{{{v}_{e}}}{{{v}_{h}}}\] \[\Rightarrow \] \[\frac{3/4}{1/4}=\frac{{{n}_{e}}}{{{n}_{h}}}\times \frac{5}{2}\] \[\Rightarrow \] \[\frac{{{n}_{e}}}{{{n}_{h}}}=\frac{6}{5}\]
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