JCECE Engineering JCECE Engineering Solved Paper-2010

  • question_answer
    An astronomical telescope has an angular magnification of magnitude \[5\] for distant objects. The separation between the objective and the eye-piece is \[36\,\,cm\] and the final image is formed at infinity. The focal length \[{{f}_{o}}\] of the objective and the focal length \[{{f}_{e}}\] of the eye-piece are

    A) \[{{f}_{o}}=45\,\,cm\]and\[{{f}_{e}}=-9\,\,cm\]

    B) \[{{f}_{o}}=-7.2\,\,cm\]and\[{{f}_{e}}=5\,\,cm\]

    C) \[{{f}_{o}}=50\,\,cm\]and\[{{f}_{e}}=10\,\,cm\]

    D)  \[{{f}_{o}}=30\,\,cm\]and\[{{f}_{e}}=6\,\,cm\]

    Correct Answer: D

    Solution :

    In this case          \[|m|=\frac{{{f}_{o}}}{{{f}_{e}}}=5\]                      ... (i) and length of telescope                 \[{{f}_{o}}+{{f}_{e}}=36\]                                             ... (ii) Solving Eqs. (i) and (ii), we get                 \[{{f}_{e}}=6\,\,cm,\,\,{{f}_{o}}=30\,\,cm\]


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