A) \[PC{{l}_{5}}PC{{l}_{3}}+C{{l}_{2}}\]
B) \[{{N}_{2}}+{{O}_{2}}2NO\]
C) \[{{N}_{2}}+3{{H}_{2}}2N{{H}_{3}}\]
D) \[2S{{O}_{3}}2S{{O}_{2}}+{{O}_{2}}\]
Correct Answer: B
Solution :
\[{{K}_{p}}={{K}_{c}}{{(RT)}^{\Delta {{n}_{g}}}}\] \[{{K}_{p}}={{K}_{c}}\]only when\[{{(RT)}^{{{\Delta }_{n}}}}=0\] [a]\[PC{{l}_{5}}PC{{l}_{3}}+C{{l}_{2}}\] \[\Delta {{n}_{g}}={{n}_{p}}-{{n}_{R}}\] \[=2-1\] \[=1\] \[\Delta {{K}_{p}}\ne {{K}_{c}}\] [b]\[{{N}_{2}}+{{O}_{2}}2NO\] \[\Delta {{n}_{g}}=2-2\] \[=0\] \[\therefore \] \[\Delta {{K}_{p}}\ne {{K}_{c}}\] [c]\[{{N}_{2}}+3{{H}_{2}}2N{{H}_{3}}\] \[\Delta {{n}_{g}}=2-4\] \[=-2\] \[\therefore \] \[{{K}_{p}}\ne {{K}_{c}}\] [d]\[2S{{O}_{3}}2S{{O}_{2}}+{{O}_{2}}\] \[\Delta {{n}_{g}}=3-2=1\] \[\therefore \] \[{{K}_{p}}\ne {{K}_{c}}\]
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