A) 2-bromo-1-propanol
B) 3-bromo-1-propanol
C) 2-bromo-2-propanol
D) 1-bromo-2-propanol
Correct Answer: D
Solution :
\[\underset{propene}{\mathop{C{{H}_{3}}CH}}\,=C{{H}_{2}}+\overset{\delta -}{\mathop{HO}}\,\overset{+}{\mathop{Br}}\,\xrightarrow{{}}C{{H}_{3}}\underset{\begin{smallmatrix} | \\ OH \\ 1-bromo-propanol \end{smallmatrix}}{\mathop{C}}\,H-C{{H}_{2}}Br\]The addition takes place according to Markownikoffs rule.
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