2. Solved Papers
  3. JCECE Engineering

JCECE Engineering JCECE Engineering Solved Paper-2011

  • question_answer
    Two pendulum have time period \[T\] and \[\frac{5T}{4}\] they start \[SHM\] at the same time form the mean position. What will be the phase difference between them after the bigger pendulum completed one oscillation

    A) \[{{45}^{o}}\]                                    

    B) \[{{90}^{o}}\]

    C)  \[{{60}^{o}}\]                                   

    D)  \[{{30}^{o}}\]

    Correct Answer: B

    Solution :

    When bigger pendulum of time period\[(5T/4)\] completes one vibration, the smaller pendulum will complete \[(5/4)\] vibration. It means the smaller pendulum will be leading the bigger pendulum by phase\[\frac{T}{4}s=\frac{\pi }{2}rad={{90}^{o}}\].


You need to login to perform this action.
You will be redirected in 3 sec spinner