2. Solved Papers
  3. JCECE Engineering

JCECE Engineering JCECE Engineering Solved Paper-2011

  • question_answer
    A dip circle lies initially in the magnetic meridian. If it is now rotated through angle \[\theta \] in the horizontal plane, then tangent of the angle of dip is changed in the ratio

    A) \[1:\cos \theta \]                            

    B) \[\cos \theta :1\]

    C)  \[1:\sin \theta \]                            

    D)  \[\sin \theta :1\]

    Correct Answer: A

    Solution :

    Here,\[\tan \delta =\frac{V}{H}\]and\[\tan \delta '=\frac{V}{H\cos \theta }\] \[\therefore \]  \[\frac{\tan \delta '}{\tan \delta }=\frac{V}{H\cos \theta }\times \frac{H}{V}\]                 \[=\frac{1}{\cos \theta }\]


You need to login to perform this action.
You will be redirected in 3 sec spinner