2. Solved Papers
  3. JCECE Engineering

JCECE Engineering JCECE Engineering Solved Paper-2011

  • question_answer
    The mass of a planet is six times that of the earth. The radius of the planet is twice that of the earth. If the escape velocity from the earth is v, then the escape velocity from the planet is

    A) \[\sqrt{3}v\]                                      

    B) \[\sqrt{2}v\]

    C)  \[\sqrt{5}v\]                                     

    D)  \[\sqrt{12}v\]

    Correct Answer: A

    Solution :

    Escape velocity from the earth                 \[{{v}_{e}}=\sqrt{\frac{2GM}{R}}\] For a given planet                 \[{{v}_{p}}=\sqrt{\frac{2G(6M)}{2R}}=\sqrt{3}{{v}_{e}}=\sqrt{3}v\]


You need to login to perform this action.
You will be redirected in 3 sec spinner