JCECE Engineering JCECE Engineering Solved Paper-2011

  • question_answer
    Moment of inertia of a uniform circular disc about a diameter is\[I\]. Its moment of inertia about an axis perpendicular to its plane and passing through a point on its rim will be

    A) \[5\,\,I\]                                             

    B) \[3\,\,I\]

    C)  \[6\,\,I\]                                            

    D)  \[4\,\,I\]

    Correct Answer: C

    Solution :

    \[I=\frac{1}{4}M{{R}^{2}}\] \[M{{R}^{2}}=4I\] We have to find                 \[I'=\frac{3}{2}M{{R}^{2}}\]                 \[=\frac{3}{2}\times 4I\]                 \[=6I\]


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