A) \[{{K}_{2}}S{{O}_{4}}\]
B) \[NaHS{{O}_{4}}\]
C) \[Sugar\]
D) \[MgS{{O}_{4}}\]
Correct Answer: D
Solution :
\[i=2\]means two ions are present in the solution. \[{{K}_{2}}S{{O}_{4}}\xrightarrow{{}}\underbrace{2{{K}^{+}}+SO_{4}^{2-}}_{3\,\,ions}\] \[NaHS{{O}_{4}}\xrightarrow{{}}\underbrace{N{{a}^{+}}+{{H}^{+}}+SO_{4}^{2-}}_{3\,\,ions}\] \[Sugar\xrightarrow{{}}No\,\,ions\] \[MgS{{O}_{4}}\xrightarrow{{}}\underbrace{M{{g}^{2+}}+SO_{4}^{2-}}_{2\,\,ions}\] Thus, van't Hoff factor is 2 for dilute solution of\[MgS{{O}_{4}}\].
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