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JCECE Engineering JCECE Engineering Solved Paper-2012

  • question_answer
    If the supply of oxygen is limited, \[{{H}_{2}}S\] reacts with \[{{O}_{2}}\] to form

    A) \[{{H}_{2}}O+S{{O}_{3}}\]                           

    B) \[{{H}_{2}}O+S\]

    C) \[{{H}_{2}}S{{O}_{4}}+S\]                            

    D) \[{{H}_{2}}O+S{{O}_{2}}\]

    Correct Answer: B

    Solution :

    In limited supply of \[{{O}_{2}},\,\,{{H}_{2}}S\] bums with blue flame and \[S\] and \[{{H}_{2}}O\] are main products.                 \[2{{H}_{2}}S+{{O}_{2}}\xrightarrow[{}]{{}}2{{H}_{2}}O+2S\]


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