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JCECE Engineering JCECE Engineering Solved Paper-2012

  • question_answer
    If\[\sin \theta +\cos \theta =\sqrt{2}\cos ({{90}^{o}}-\theta )\], then find the value of\[\cot \theta \]

    A) \[\frac{1}{2}\]                                   

    B) \[0\]

    C) \[-1\]                                    

    D) \[2\]

    Correct Answer: B

    Solution :

                    \[\sin \theta +\cos \theta =\sqrt{2}\cos ({{90}^{o}}-\theta )\]                 \[\sin \theta +\cos \theta =\sqrt{2}\sin \theta \] \[\Rightarrow \]               \[\cos \theta =(\sqrt{2}-1)\sin \theta \] \[\Rightarrow \]               \[\cot \theta =\sqrt{2}-1\]


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