A) \[AP\]
B) \[GP\]
C) \[HP\]
D) None of these
Correct Answer: C
Solution :
\[\log (p+r)+\log (p+r-2q)=2\log (p-r)\] \[\Rightarrow \] \[\log [(p+r)(p+r-2q)]=\log {{(p-r)}^{2}}\] \[\Rightarrow \] \[{{p}^{2}}+pr-2pq+pr+{{r}^{2}}-2qr\] \[={{p}^{2}}+{{r}^{2}}-2pr\] \[\Rightarrow \] \[4pr-2pq-2qr=0\] \[\Rightarrow \] \[2pr=pq+qr\] \[\Rightarrow \] \[2pr=q(p+r)\] \[\Rightarrow \] \[q=\frac{2pr}{p+r}\] \[\Rightarrow \]\[p,\,\,q\]and \[r\] are in\[HP\].
You need to login to perform this action.
You will be redirected in
3 sec
