A) \[5\,\,s/day\]
B) \[10.3\,\,s/day\]
C) \[20.6\,\,s/day\]
D) \[20\,\,\min /day\]
Correct Answer: B
Solution :
As,\[{{T}_{2}}={{T}_{1}}\sqrt{{{I}_{2}}/{{I}_{1}}}\] \[={{T}_{1}}\times \sqrt{\frac{{{l}_{1}}[\{1+12\times {{10}^{-6}}\times (40-20)\}]}{{{l}_{1}}}}\] \[={{T}_{1}}\sqrt{1+240\times {{10}^{-6}}}\] \[\therefore \] \[\frac{{{T}_{2}}-{{T}_{1}}}{{{T}_{1}}}={{(1+240\times {{10}^{-6}})}^{1/2}}-1\] \[=120\times {{10}^{-6}}\] or \[{{T}_{2}}-{{T}_{1}}=120\times {{10}^{-6}}\times (24\times 60\times 60)s\] \[=10.36\,\,s/day\] It will be a loss as\[{{T}_{2}}>{{T}_{1}}\].
You need to login to perform this action.
You will be redirected in
3 sec
