A) \[C{{H}_{3}}CH(OH)CH(Cl){{C}_{2}}{{H}_{5}}\]
B) \[C{{H}_{3}}CH(OH)CH(OH)C{{H}_{3}}\]
C) \[{{C}_{2}}{{H}_{5}}CH(OH)CH(OH)C{{H}_{3}}\]
D) \[HOC{{H}_{2}}CH(Cl)C{{H}_{3}}\]
Correct Answer: B
Solution :
Plane of symmetry Compound have plane of symmetry thus it has me so form.
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