JCECE Engineering JCECE Engineering Solved Paper-2014

  • question_answer
    A mass of \[0.5\,\,kg\] moving with a speed of \[1.5\,\,m{{s}^{-1}}\] on a horizontal smooth surface, collides with a nearly weightless spring of force constant\[k=50\,\,N{{m}^{-1}}\]. The maximum compression of the spring would be

    A) \[0.15\,\,m\]                     

    B) \[0.23\,\,m\]

    C) \[1.6\,\,m\]                       

    D)  \[0.4\,\,m\]

    Correct Answer: A

    Solution :

    By the law of conservation of .energy. Kinetic energy of mass = energy stored in spring                 \[\frac{1}{2}m{{v}^{2}}=\frac{1}{2}k{{x}^{2}}\] The maximum compression of the spring                 \[x=\sqrt{\frac{m{{v}^{2}}}{k}}\]                 \[x=\sqrt{\frac{0.5\times 1.5\times 1.5}{50}}=0.15\,\,m\]


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