JCECE Engineering JCECE Engineering Solved Paper-2014

  • question_answer
    A particle of mass \[{{m}_{1}}\] moves with velocity \[{{\upsilon }_{1}}\] and collides with another particle at rest of equal mass. The velocity of the second particle after the elastic collision is

    A) \[3{{v}_{1}}\]                                    

    B) \[{{v}_{1}}\]

    C)  \[-{{v}_{1}}\]                                    

    D)  \[0\]

    Correct Answer: B

    Solution :

    For elastic collision                 \[{{v}_{2}}=\left( \frac{{{m}_{2}}-{{m}_{1}}}{{{m}_{1}}+{{m}_{2}}} \right){{u}_{2}}+\frac{2{{m}_{1}}{{u}_{1}}}{{{m}_{1}}+{{m}_{2}}}\] Because another body is initially at rest \[i.e.,\] \[{{u}_{2}}=0\] Velocity of the second particle                 \[{{v}_{2}}=\frac{2{{m}_{1}}{{v}_{1}}}{2{{m}_{1}}}\]                        \[\left( \begin{align}   & \because \,\,{{u}_{1}}={{v}_{1}} \\  & {{m}_{2}}={{m}_{1}} \\ \end{align} \right)\]                 \[{{v}_{2}}={{v}_{1}}\]


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