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JCECE Engineering JCECE Engineering Solved Paper-2014

  • question_answer
    The height vertically above the earth's surface at which the acceleration due to gravity becomes \[1%\] of its value at the surface is (\[R\] is the radius of the earth)

    A) \[8R\]                                   

    B) \[9R\]

    C) \[10R\]                                

    D)  \[20R\]

    Correct Answer: B

    Solution :

    \[g'=\frac{g}{{{\left( 1+\frac{h}{R} \right)}^{2}}}\Rightarrow \frac{g}{100}=\frac{g}{{{\left( 1+\frac{h}{R} \right)}^{2}}}\]                 \[{{\left( 1+\frac{h}{R} \right)}^{2}}=100\]                 \[h=9R\]


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