JCECE Engineering JCECE Engineering Solved Paper-2014

  • question_answer
    \[X\]and\[Y\], two metallic coils are arranged in such a way that, when steady change in current flowing in \[X\] coil is\[4\,\,A\], change in magnetic flux associated with coil \[Y\] is\[0.4\,\,Wb\]. Mutual inductance of the system of these coils is

    A) \[0.2\,\,H\]                        

    B) \[5\,\,H\]

    C) \[0.8\,\,H\]                        

    D) \[0.1\,\,H\]

    Correct Answer: D

    Solution :

    We know that, the magnetic flux associated with coil \[Y\] is directly proportional to current flowing in \[X\] coil.                 \[{{\phi }_{y}}\propto {{l}_{x}}\] Here,\[{{\phi }_{y}}=\]change in magnetic flux in coil\[Y\] \[{{l}_{x}}=\]change in current in coil\[X\] \[M=\]mutual inductance We have\[{{\phi }_{y}}=M{{l}_{x}}\]                 \[{{l}_{x}}=4\,\,A\] and        \[{{\phi }_{y}}=0.4\,\,Wb\]                 \[0.4=M\times 4\]                 \[M=\frac{0.4}{4}=0.1H\]


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