A) 3 and 1
B) 3 and 3
C) 3 and 2
D) 1 and 3
Correct Answer: A
Solution :
The focal length of each portion of lens corresponding to a certain material will be given by \[\frac{1}{f}=(\mu -1)\left( \frac{1}{{{R}_{1}}}+\frac{1}{{{R}_{2}}} \right)\] \[\left[ \because \,\,\left( \frac{1}{{{R}_{1}}}+\frac{1}{{{R}_{2}}} \right)\text{is}\,\,\text{constant}\,\,\text{for}\,\,\text{all}\,\,\text{lenses} \right]\] Thus, for lens\[P\], three different portions passes three different focal lengths and hence corresponding to the same object distance there will be three images for each. For lens\[Q\], the combination of the three lenses would effectively act as a single lens and hence only one image is formed.
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