A) dithionous acid
B) sulphurous acid
C) thionous acid
D) phyrosulphuric acid
Correct Answer: A
Solution :
\[\underset{Dithionous\,\,acid}{\mathop{H-O-\overset{\begin{smallmatrix} O \\ || \end{smallmatrix}}{\mathop{S}}\,-\overset{\begin{smallmatrix} O \\ || \end{smallmatrix}}{\mathop{S}}\,-O-H}}\,\] Let oxidation state of sulphur is x. \[2\times 1+4\times (-2)+2x=0\] \[2-8+2x=0\] \[2x=+6\] \[x=+3\]
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