JCECE Engineering JCECE Engineering Solved Paper-2015

  • question_answer
    The difference of water molecules in gypsum and plaster of Paris is

    A) \[\frac{5}{2}\]                                   

    B) \[2\]

    C) \[\frac{1}{2}\]                                   

    D) \[1\frac{1}{2}\]

    Correct Answer: D

    Solution :

    Formula of gypsum\[=CaS{{O}_{4}}\cdot 2{{H}_{2}}O\] Formula of plaster of Paris\[=CaS{{O}_{4}}\cdot \frac{1}{2}{{H}_{2}}O\] Thus, difference of water molecule                 \[=2{{H}_{2}}O-\frac{1}{2}{{H}_{2}}O=1\frac{1}{2}{{H}_{2}}O\]


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