question_answer

The structure of \[I{{F}_{5}}\] can be described as

A)                              

B)

C)                              

D)   None of these

Correct Answer: C

Solution :

Number of hybrid orbitals = number of\[bp+\]number of\[lp\] \[=5+1=6\] Thus, hybridisation is \[s{{p}^{3}}{{d}^{2}}\] but geometry due to the presence of one lone pair is square pyramidal.