JCECE Medical JCECE Medical Solved Paper-2002

  • question_answer
    If the degrees of freedom of the molecules of a gas are n, the ratio of its two specific heats \[({{C}_{P}}+{{C}_{V}})\]will be:

    A) \[1+\frac{2}{n}\]

    B) \[1-\frac{2}{n}\]

    C)  \[1+\frac{1}{n}\]

    D)  \[2-\frac{1}{n}\]

    Correct Answer: A

    Solution :

     Key Idea: Mayors formula is \[{{C}_{P}}-{{C}_{V}}=R.\] Internal energy of a gram mole of a perfect gas having n degrees of freedom is \[U=N\left( n.\frac{1}{2}kt \right)=\frac{n}{2}RT\] \[{{C}_{V}}=\frac{dU}{dt}=\frac{d}{dt}\left( \frac{n}{2}RT \right)=\frac{n}{2}R\] From Mayors formula \[{{C}_{P}}-{{C}_{V}}=R\]              \[\Rightarrow \] \[{{C}_{P}}=R+{{C}_{V}}\] \[\Rightarrow \] \[{{C}_{P}}=R+\frac{n}{2}R=\left( \frac{n}{2}+1 \right)R\] \[\therefore \] \[\gamma =\frac{{{C}_{P}}}{{{C}_{V}}}=\frac{\left( \frac{n}{2}+1 \right)R}{\frac{n}{2}R}=1+\frac{2}{n}\]


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