A) 190 MeV
B) 931 MeV
C) 93.1 MeV
D) 931 J
Correct Answer: B
Solution :
Key Idea: Mass of 1 proton = 1 amu \[=1.66\times {{10}^{-27}}kg\] \[\therefore \]energy equivalent to \[1\,amu=m{{c}^{2}}\] where\[m=\]mass of proton \[=1.66\times {{10}^{-27}}kg\] \[c=\]velocity of light\[=2.98\times {{10}^{8}}\,m{{s}^{-1}}\] \[\therefore \] \[E=1.66\times {{10}^{-27}}\times {{(2.98\times {{10}^{8}})}^{2}}\] \[=1.4925\times {{10}^{-10}}J\] \[=931.65\,MeV\]\[(\because \,1eV=1.602\times {{10}^{-19}}J)\] \[\approx \,931\,MeV\]
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