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JCECE Medical JCECE Medical Solved Paper-2002

  • question_answer
    In the following nuclear reaction \[_{2}H{{e}^{3}}+{{\,}_{Z}}{{X}^{a}}\xrightarrow{{}}{{\,}_{Z+1}}{{Y}^{a+2}}+Q.\]What is Q?

    A)  Neutron       

    B)  Proton

    C)  Positron       

    D)  Electron

    Correct Answer: B

    Solution :

     Key Idea: (i) Sum of atomic masses of reactants  is equal to sum of atomic masses of products (ii) Sum of atomic numbers of reactants is  equal to sum of atomic numbers of products. \[_{2}H{{e}^{3}}+{{\,}_{Z}}{{X}^{a}}\xrightarrow{{}}{{\,}_{Z+1}}{{Y}^{a+2}}+{{\,}_{1}}{{H}^{1}}\] \[\therefore \] Q is proton \[({{\,}_{1}}{{H}^{1}})\]


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