JCECE Medical JCECE Medical Solved Paper-2003

  • question_answer
    In a triode valve, when the plate potential is increased from 200 V to 220 V and grid potential is decreased from \[-0.5\text{ V}\]to \[-\text{ 1}\text{.3 V,}\] there is 1 no change in plate current. The amplification factor of the triode is:

    A)  25             

    B)  14

    C)  11             

    D)  73

    Correct Answer: A

    Solution :

     Amplification factor is defined as the ratio of change in plate potential \[(\Delta {{V}_{p}})\] to produce certain change in plate current \[(\Delta {{i}_{p}})\] to the change in grid potential \[({{\Delta }_{g}})\] for the same change in plate current i.e,. \[\mu =-{{\left( \frac{\Delta {{V}_{p}}}{\Delta {{V}_{g}}} \right)}_{\Delta {{i}_{p}}=\,\text{constant}}}\] Here, \[\Delta {{V}_{p}}=220-200=20\,V,\] \[\Delta {{V}_{g}}=-1.3-(-0.5)\] \[=-0.8\,V\] \[\mu =-\left( \frac{20}{-0.8} \right)=25\] Note: Amplification factor is unitless and dimensionless.


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