A) 6400 km
B) 8200 km
C) 4800 km
D) 1600 km
Correct Answer: D
Solution :
Acceleration due to gravity at a height h is given by \[g=g\left( 1-\frac{2h}{R} \right)\] ?(i) At height \[h,\,g=\frac{g}{2}\] (given) Thus, Eq. (i) becomes \[\therefore \] \[\frac{g}{2}=g\left( 1-\frac{2h}{R} \right)\] or \[\frac{1}{2}=1-\frac{2h}{R}\] or \[\frac{2h}{R}=1-\frac{1}{2}=\frac{1}{2}\] or \[h=\frac{R}{4}=\frac{6400}{4}=1600\,km\]You need to login to perform this action.
You will be redirected in
3 sec