A) \[\frac{n}{3}\frac{h}{\pi }\]
B) \[\frac{n}{2}\frac{h}{\pi }\]
C) \[\frac{h}{4\pi }\]
D) \[\sqrt{l(l+1)}.\frac{h}{2\pi }\]
Correct Answer: B
Solution :
According to Bohrs theory, angular momentum of an orbit is always a multiple of \[\frac{h}{2\pi },\]i.e., equal to \[\frac{n\,h}{2\pi }.\]
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