A) \[mol\,{{L}^{-1}}{{s}^{-1}}\]
B) \[mo{{l}^{-1}}\,L{{s}^{-1}}\]
C) \[{{s}^{-1}}\]
D) \[mo{{l}^{2}}{{L}^{-2}}{{s}^{-1}}\]
Correct Answer: C
Solution :
Key Idea: For reaction of nth order \[k=\frac{1}{time}\times \frac{1}{{{(conc.)}^{n-1}}}\] For first order reaction\[n=1\] \[\therefore \] \[k=\frac{1}{time}\times \frac{1}{{{(conc.)}^{1-1}}}=\frac{1}{time}=tim{{e}^{-1}}\] \[={{s}^{-1}}\]
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