A) 3.4 g
B) 0.034 g
C) 0.34 g
D) 0.17g
Correct Answer: C
Solution :
Key Idea: First write balanced chemical reaction and then find the answer. \[BaC{{l}_{2}}+{{H}_{2}}S\xrightarrow{{}}BaS+2HCl\] Molecular mass of\[{{H}_{2}}S=1\times 2+32=34\] Molecular mass of \[BaS=137+32=169\] Given mass of\[BaS=1.69\,g\] According to reaction. \[\because \]\[169\,g\]of \[\text{BaS}\]is obtained by \[\text{=}\,\text{34}\,\text{g}\,\]of \[{{H}_{2}}S\] \[\therefore \]1.69 g of \[\text{BaS}\]is obtained by \[=\frac{34}{169}\times 1.69\] \[=0.34\,g\,\text{of}\,{{\text{H}}_{\text{2}}}\text{S}\]
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