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JCECE Medical JCECE Medical Solved Paper-2005

  • question_answer
    The coefficient of mutual inductance between the primary and secondary of the coil is 5 H. A current of 10 A is cut-off in 0.5 s. The induced emf is:

    A)  1 V          

    B)  10 V

    C)  5 V           

    D)  100 V

    Correct Answer: D

    Solution :

     From Faraday?s law of electromagnetic induction, the induced emf [e] is given by \[e=-M\frac{di}{dt}\] Given, \[M=5H,di=10A,dt=0.5s\] \[\therefore \] \[e=-5\times \frac{10}{0.5}=-100\,V\] Note: Minus sign in the relation is reflection of Lenz's law.


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